Integrand size = 19, antiderivative size = 167 \[ \int \left (a+b x^3\right )^2 \left (c+d x^3\right )^q \, dx=-\frac {b (4 b c-a d (10+3 q)) x \left (c+d x^3\right )^{1+q}}{d^2 (4+3 q) (7+3 q)}+\frac {b x \left (a+b x^3\right ) \left (c+d x^3\right )^{1+q}}{d (7+3 q)}+\frac {\left (4 b^2 c^2-2 a b c d (7+3 q)+a^2 d^2 \left (28+33 q+9 q^2\right )\right ) x \left (c+d x^3\right )^{1+q} \operatorname {Hypergeometric2F1}\left (1,\frac {4}{3}+q,\frac {4}{3},-\frac {d x^3}{c}\right )}{c d^2 (4+3 q) (7+3 q)} \]
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Time = 0.09 (sec) , antiderivative size = 176, normalized size of antiderivative = 1.05, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.211, Rules used = {427, 396, 252, 251} \[ \int \left (a+b x^3\right )^2 \left (c+d x^3\right )^q \, dx=\frac {x \left (c+d x^3\right )^q \left (\frac {d x^3}{c}+1\right )^{-q} \left (a^2 d^2 \left (9 q^2+33 q+28\right )-2 a b c d (3 q+7)+4 b^2 c^2\right ) \operatorname {Hypergeometric2F1}\left (\frac {1}{3},-q,\frac {4}{3},-\frac {d x^3}{c}\right )}{d^2 (3 q+4) (3 q+7)}-\frac {b x \left (c+d x^3\right )^{q+1} (4 b c-a d (3 q+10))}{d^2 (3 q+4) (3 q+7)}+\frac {b x \left (a+b x^3\right ) \left (c+d x^3\right )^{q+1}}{d (3 q+7)} \]
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Rule 251
Rule 252
Rule 396
Rule 427
Rubi steps \begin{align*} \text {integral}& = \frac {b x \left (a+b x^3\right ) \left (c+d x^3\right )^{1+q}}{d (7+3 q)}+\frac {\int \left (c+d x^3\right )^q \left (-a (b c-a d (7+3 q))-b (4 b c-a d (10+3 q)) x^3\right ) \, dx}{d (7+3 q)} \\ & = -\frac {b (4 b c-a d (10+3 q)) x \left (c+d x^3\right )^{1+q}}{d^2 (4+3 q) (7+3 q)}+\frac {b x \left (a+b x^3\right ) \left (c+d x^3\right )^{1+q}}{d (7+3 q)}+\frac {\left (4 b^2 c^2-2 a b c d (7+3 q)+a^2 d^2 \left (28+33 q+9 q^2\right )\right ) \int \left (c+d x^3\right )^q \, dx}{d^2 (4+3 q) (7+3 q)} \\ & = -\frac {b (4 b c-a d (10+3 q)) x \left (c+d x^3\right )^{1+q}}{d^2 (4+3 q) (7+3 q)}+\frac {b x \left (a+b x^3\right ) \left (c+d x^3\right )^{1+q}}{d (7+3 q)}+\frac {\left (\left (4 b^2 c^2-2 a b c d (7+3 q)+a^2 d^2 \left (28+33 q+9 q^2\right )\right ) \left (c+d x^3\right )^q \left (1+\frac {d x^3}{c}\right )^{-q}\right ) \int \left (1+\frac {d x^3}{c}\right )^q \, dx}{d^2 (4+3 q) (7+3 q)} \\ & = -\frac {b (4 b c-a d (10+3 q)) x \left (c+d x^3\right )^{1+q}}{d^2 (4+3 q) (7+3 q)}+\frac {b x \left (a+b x^3\right ) \left (c+d x^3\right )^{1+q}}{d (7+3 q)}+\frac {\left (4 b^2 c^2-2 a b c d (7+3 q)+a^2 d^2 \left (28+33 q+9 q^2\right )\right ) x \left (c+d x^3\right )^q \left (1+\frac {d x^3}{c}\right )^{-q} \, _2F_1\left (\frac {1}{3},-q;\frac {4}{3};-\frac {d x^3}{c}\right )}{d^2 (4+3 q) (7+3 q)} \\ \end{align*}
Time = 0.21 (sec) , antiderivative size = 106, normalized size of antiderivative = 0.63 \[ \int \left (a+b x^3\right )^2 \left (c+d x^3\right )^q \, dx=\frac {1}{14} x \left (c+d x^3\right )^q \left (1+\frac {d x^3}{c}\right )^{-q} \left (14 a^2 \operatorname {Hypergeometric2F1}\left (\frac {1}{3},-q,\frac {4}{3},-\frac {d x^3}{c}\right )+b x^3 \left (7 a \operatorname {Hypergeometric2F1}\left (\frac {4}{3},-q,\frac {7}{3},-\frac {d x^3}{c}\right )+2 b x^3 \operatorname {Hypergeometric2F1}\left (\frac {7}{3},-q,\frac {10}{3},-\frac {d x^3}{c}\right )\right )\right ) \]
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\[\int \left (b \,x^{3}+a \right )^{2} \left (d \,x^{3}+c \right )^{q}d x\]
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\[ \int \left (a+b x^3\right )^2 \left (c+d x^3\right )^q \, dx=\int { {\left (b x^{3} + a\right )}^{2} {\left (d x^{3} + c\right )}^{q} \,d x } \]
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Result contains complex when optimal does not.
Time = 90.09 (sec) , antiderivative size = 121, normalized size of antiderivative = 0.72 \[ \int \left (a+b x^3\right )^2 \left (c+d x^3\right )^q \, dx=\frac {a^{2} c^{q} x \Gamma \left (\frac {1}{3}\right ) {{}_{2}F_{1}\left (\begin {matrix} \frac {1}{3}, - q \\ \frac {4}{3} \end {matrix}\middle | {\frac {d x^{3} e^{i \pi }}{c}} \right )}}{3 \Gamma \left (\frac {4}{3}\right )} + \frac {2 a b c^{q} x^{4} \Gamma \left (\frac {4}{3}\right ) {{}_{2}F_{1}\left (\begin {matrix} \frac {4}{3}, - q \\ \frac {7}{3} \end {matrix}\middle | {\frac {d x^{3} e^{i \pi }}{c}} \right )}}{3 \Gamma \left (\frac {7}{3}\right )} + \frac {b^{2} c^{q} x^{7} \Gamma \left (\frac {7}{3}\right ) {{}_{2}F_{1}\left (\begin {matrix} \frac {7}{3}, - q \\ \frac {10}{3} \end {matrix}\middle | {\frac {d x^{3} e^{i \pi }}{c}} \right )}}{3 \Gamma \left (\frac {10}{3}\right )} \]
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\[ \int \left (a+b x^3\right )^2 \left (c+d x^3\right )^q \, dx=\int { {\left (b x^{3} + a\right )}^{2} {\left (d x^{3} + c\right )}^{q} \,d x } \]
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\[ \int \left (a+b x^3\right )^2 \left (c+d x^3\right )^q \, dx=\int { {\left (b x^{3} + a\right )}^{2} {\left (d x^{3} + c\right )}^{q} \,d x } \]
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Timed out. \[ \int \left (a+b x^3\right )^2 \left (c+d x^3\right )^q \, dx=\int {\left (b\,x^3+a\right )}^2\,{\left (d\,x^3+c\right )}^q \,d x \]
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